Please help Calculate the hydrostatic pressure P2 atm requir

Please help

Calculate the hydrostatic pressure (P_2, atm) required to prevent expansion (Delta V = 0) of a one cubic meter cube of copper when temperature is increased from T_1 = 27Degree C (300 K) at P_1 = 1 atm to T_2 = 127Degree C (400 K). Assume Alpha, k constant. K = - 1/v Partial Differential V/Partial Differential P|_T = 7.5Times 10^-6 (atm)^-1 Alpha = 1/v Partial Differential V/Partial Differential T|_P = 4.2 Times 10^-5 (K)^-1 Integral x^ndx = x^n+1/n+1 Integral dx/x = lnx Integral adv = ar - Integral rdu Integral lnxdx = xlnx - x

Solution

GIVEN:- P1 = 1 atm, T1 = 300 K, T2 = 400 K, dV = 0

TO-FIND:- P2 = ?

SOLUTION:- By formula P2/P1 = (T2/T1) ^ (/-1) (Here = 1.4)

So P2/1 = (400/300) ^ (1.4/1.4-1)

i.e. P2 = 1.3333 ^ 3.5 = 2.74 atm

Hydrostatic pressure P2 = 2.74 atm (ANSWER)