If arcsin6x4y 15708 and arccos2xy 10472 find the value of

If arcsin(6x+4y) = 1.5708 and arccos(2x+y) = 1.0472, find the value of x.

Thanks!

Solution

Considering 1.5705 and 1.0472 in radians

arc sin(6x+4y)=1.5705

6x+4y=sin^-11.5705

6x+4y=1

Arc cos (2x+y)=1.0472

2x+y=cos^-11.0472

2x+y=1/2

So we have two equations

2x +y=1/2

6x+4y=1

Solving these two equations,we get

X=1/2 and y=-1/2