1 The reactant concentration in a firstorder reaction was 90

1)    The reactant concentration in a first-order reaction was 9.00

Solution

1st order reaction

ln(Ca0/Ca) = Kt

ln(Ca0) = K*15 - 2.41

ln(Ca0) = K*100 - 5.4


K*15 - 2.41 = K*100 - 5.4

85K = 2.99

k= 0.035 sec^-1


2nd order

1/Ca - 1/Ca0 = kt


1/Ca0 = 1/Ca - kt


1/Ca0 = = 1/0.33 - 140*K

1/Ca0 = = 1/0.015 - 840*K


1/0.33 - 140*K = 1/0.015 - 840*K


700K = 700/11

k = 1/11 = 0.0909 L* mol?1 *s?1

1) The reactant concentration in a first-order reaction was 9.00Solution1st order reaction ln(Ca0/Ca) = Kt ln(Ca0) = K*15 - 2.41 ln(Ca0) = K*100 - 5.4 K*15 - 2.

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