1 The reactant concentration in a firstorder reaction was 90
1) The reactant concentration in a first-order reaction was 9.00
Solution
1st order reaction
ln(Ca0/Ca) = Kt
ln(Ca0) = K*15 - 2.41
ln(Ca0) = K*100 - 5.4
K*15 - 2.41 = K*100 - 5.4
85K = 2.99
k= 0.035 sec^-1
2nd order
1/Ca - 1/Ca0 = kt
1/Ca0 = 1/Ca - kt
1/Ca0 = = 1/0.33 - 140*K
1/Ca0 = = 1/0.015 - 840*K
1/0.33 - 140*K = 1/0.015 - 840*K
700K = 700/11
k = 1/11 = 0.0909 L* mol?1 *s?1
