Help to solve the example11 in the image above A farm worker

Help to solve the example#11 in the image above.

A farm worker was paid a weekly wage of $415.20 for a 44-hour work week. As a result of a new labor contract, he is paid $431.40 a week for a 40-hour work week with time and one-half pay for time worked in excess of 40 hours in any work week. If he continues to work 44 hours weekly under the new contract, the amount by which his average hourly rate for a 44-hour work week under the new contract exceeds the hourly rate previously paid him lies between and, inclusive. 800 c; $1.00 $1.00; $1.20 $1.25; $1.45 $1.50; $1.70 The sum of 4 feet 3 1/4 inches, 7 feet 2 1/2 inches, and 11 feet 1/4 inch is inches. feet 21;6 1/4 22; 6 23;5 24; 5 3/4

Solution

In Case 1.

wage/hr = 415.20/44 = $9.44

In case 2

wage/hr = 431.40/40 = $10.79

Now he works 44 hrs in case B than

wage earned in 4 hr = $10.79*4*0.5 = 21.58

Total wage earned in 44 hrs = 431.40 + 21.58 = $452.98

Now his wage/hr will be = 452.98/44 = $10.30

Difference between wages = 10.30 - 9.44 = $0.86 = 86 cents

Correct option is A.