Using C or C write a program which starts the command ls la

Using C or C++, write a program which starts the command ”ls -la” using a fork() followed by an exec() (any of the exec functions will work). Use a UNIX pipe system call to send the output of ls -la back to the parent, read it using the read() function, and then write it to the console using the write() function

Solution

As per my understanding I am providing the solution, if any thing is remaining then please tell me.

Source Code:

#include<unistd.h>
#include <sys/wait.h>
#include <assert.h>
#include <stdio.h>
#include<stdio.h>
#include<stdlib.h>
int main( void )
{     
        int pfildes[2];
        pid_t pid;
        char buf;
        if (pipe(pfildes) == -1)    {perror(\"demo\"); exit(1);}
            if ((pid = fork()) == -1)   {perror(\"demo\"); exit(1);}
            else if (pid == 0) {     
            printf(\"Child process\");
          close(pfildes[0]);    /* close read end of pipe               */
          execlp(\"ls\",\"ls\",\"-la\",NULL);
          close(pfildes[1]);    /* close excess fildes                  */
          perror(\"demo1\");       /* still around? exec failed           */
          _exit(1);             /* no flush                             */
        }
    else {                      /* parent: \"/usr/bin/wc\"               */
            printf(\"Parrent process\");
          close(pfildes[1]);    /* close write end of pipe              */
        while (read(pfildes[0], &buf, 1) > 0)
            write(STDOUT_FILENO, &buf, 1);
          close(pfildes[0]);    /* close excess fildes                  */
          perror(\"demo2\");       /* still around? exec failed           */
          exit(1);            /* parent flushes                       */
        }
}