A 538g piece of copper tubing is heated to 895 degrees Celsi

A 538-g piece of copper tubing is heated to 89.5 degrees Celsius and placed in a insulated vessel containing 159 g of water at 22.8 degrees Celsius. Assuming no loss of water and a heat capacity for the vessel at 10.0 J/degrees Celsius, what is the final temperature of the system? (c of copper = .387J/g degrees Celsius)

Solution

Q = mcT

Q = heat energy (Joules, J), m = mass of a substance (kg)

c = specific heat (units J/kgK), is a symbol meaning \"the change in\"

T = change in temperature (Kelvins, K)

Heat lost by copper = Heat gained by water + heat abosrbed by vessel

Using the above equation we can calculate the final temperature

538 x 0.387 x (89.5 - Tf) = 159 x 4.184 x (Tf - 22.8) + (Tf-22.8) 10

18634.437 - 208.206 Tf = 665.256 Tf - 15167.83 + 10Tf- 228

883.462 Tf = 34030.2738

Tf = 38.51 Deg Cel

The final temperature of the system is  38.51 Deg Cel