If 500 mL of a solution containing 100 g of barium nitrate 1

If 500 mL of a solution containing 1.00 g of barium nitrate (199.33g/mol) is combined with 500 mL of a solution containing 1.00 g of sodium sulfate (142.03 g/mol) , will there be parcipitate? Barium sulfate has a Ksp= 9.1x10^-11.

A.) Barium nitrate will ppt

B.) Barium sulfate will ppt

c.) sodium nitrate will ppt

d.) it is impossible to tell

e.) there will be no ppt

Please show work if you can! Thank you!

Solution

Barium nitrate = conc = 1/199.33*0.5 = 0.01M

moles of Barium nitrate = 0.005

sodium sulfate conc = 1/ 142.03 *0.5 = 0.014M

moles of sodium sulfate = 0.007

Q for Barium nitrate = 0.005*0.005= 25*10-6

Q for Barium sulfate = 0.005*0.007 =35*10-6

so Q> Ksp

so

B Barium sulfate will ppt