7 A chemist wants to make 72 L of a 0350 M CaClh solution Ho

7. A chemist wants to make 7.2 L of a 0.350 M CaClh solution. How many grams of CaCl2 should the chemist use?

Molarity of solution = 0.350M, mass of CaCl2 = ?, Volume of solution = 7.2L = 7200 mL

Molarity of solution, M = moles of CaCl2 x 1000 / volume of solution (mL)

So, moles of CaCl2 = Molarity of solution x volume of solution / 1000

moles of CaCl2 = 0.350 x 7200 / 1000

moles of CaCl2 = 0.252 mole

Now, mass of CaCl2 = 0.252 x molar mass of CaCl2

mass of CaCl2 = 0.252 x 110.98

= 27.96 g of CaCl2