A stone thrown upward with an initial velocity of 208 feet p

A stone thrown upward with an initial velocity of 208 feet per second will attach a height of h feet in t seconds, described by the equation h(t) shown below. Answer parts(a) and(d). H(t) = 208t - 18 t^2, 0sts 13 What is the domain of h? [0, 13](Type your answer in interval notation.) Find h(3), h(8), and h(9). h(3) = ___________________ (simplify your answer.) h(8) = _____________________ (simplify your answer.) h(9) = _____________________ (simplify your answer.) How long will it take the stone to hit the ground? _______________ sec Sketch a graph of y = h(t). Choose the correct graph of the function shown below.

Solution

h(t) = 208t - 16t^2

Domain : [ 0, 13 ]

h(3) = 208*3 - 16*9 = 480 ft

h(6) = 208*6 - 16*36 = 672 ft

h(9) = 208*9 - 16*81 = 576 ft

How long it takes to reach ground : h(t) = 0\'

208t - 16t^2 =0 ; t( 208 - 16t) =0 ; t =0 , 208/16

t = 13 sec to reach ground

Graph option D