Using the monoalphabetic cipher, part of the ciphertext is the following: lutk tk luf lfkl
(I have left a blank space between the words to make the problem easier).
The following are the approximate relative frequencies of the whole ciphertext:
f:12,l:11,j:8,x:8,t:7,v:7,e:7
o:5,g:4,h:4,u:4,n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1
b:0,c:0,p:0,s:0
You have to figure out what is the plaintext corresponding to the above ciphertext segment
Using the monoalphabetic cipher, part of the ciphertext is the following: lutk tk luf lfkl
(I have left a blank space between the words to make the problem easier).
The following are the approximate relative frequencies of the whole ciphertext:
f:12,l:11,j:8,x:8,t:7,v:7,e:7
o:5,g:4,h:4,u:4,n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1
b:0,c:0,p:0,s:0
You have to figure out what is the plaintext corresponding to the above ciphertext segment
Using the monoalphabetic cipher, part of the ciphertext is the following: lutk tk luf lfkl
(I have left a blank space between the words to make the problem easier).
The following are the approximate relative frequencies of the whole ciphertext:
f:12,l:11,j:8,x:8,t:7,v:7,e:7
o:5,g:4,h:4,u:4,n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1
b:0,c:0,p:0,s:0
You have to figure out what is the plaintext corresponding to the above ciphertext segment
Ans: Here the Encrypted text is :- lutk tk luf lfkl
The relative frequency of cipher is :- f:12, :11, j:8, x:8, t:7, v:7, e:7, o:5, g:4, h:4, u:4, n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1, b:0,c:0,p:0,s:0
Normally,
In monoalphabatic substitution encryption, Relative frequency of character is E:12(for being a vowel), T:9(for being a consonant) and also most relative combined letters are TH(in case of consonant) and EA (in case of Vowel).
Here, In cipher text we have L - 4 times, k- 3 times and t- 2, u-2, f-2 times
Now using and analysing Normal English realative frequency to the cipher text which is = lutk tk luf lfkl=
THIS IS THE TEST
here lu stands for TH (remember most frequent combined consonant), Replace l = T, u = H in the cipher
and after analysing l = T, u = H, t = I, k = S, f = E.
So, Plain text would be THIS IS THE TEST
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