If cos z and sin r 13 0 find sin2x O 600169 O 1213 O120169

If cos z- and sin r > 13 0 find sin(2x) O -600/169 O 12/13 O-120/169 O 119/169

Solution

Given that cosx=-12/13 sinx>0

Calculate the value of sin2x

sinx= sqrt(13^2-12^2)/13

         =5/13

Now, we know that sin2x= 2sinxcosx

                subsituting the above values

                              =2*(5/13)*(-12/13)

                              =-120/169=answer