Can someone explain why ex 1xx22 for x0Solution According t

Can someone explain why e^x > 1+x+x^2/2 for x>0

According to the rule; we should consider the -ve curves for \"<\" sign so; x<0 and x>1. However, the correct ranges are x<0 or 01 doesn\'t; How does the rule change for even exponents and odd exponents.

$Can someone explain why e^x > 1+x+x^2/2 for x>0Solution According to the rule; we should consider the -ve curves for \$