54 Theta 4 r 6 cm 55 theta pi r 2 ft 56 theta 5 pi3 r 3

54. Theta =/4; r = 6 cm 55. theta = pi; r = 2 ft 56. theta = 5 pi/3; r = 30 in In numbers 57 - 60, change theta to radians and then find the area of the sector using the formula A = 1/2 r^2 theta. Compare results with those from exercises 49 - 52. 57. theta = 60 degree; r = 12 cm 58. theta = 90 degree; r = 10 in 59. theta = 225 degree; r = 4 ft 60. theta = 150 degree; r = 12 cm 69. A bicycle has wheels measuring 26 inches in diameter. If the bicycle is traveling at a rate of 20 miles hour find the wheels\' rate of turn in

Solution

theta = 150 degrees = 150 *(pi)/180 = 2.617 rad (pi = 22/7)

Area = 0.5 *r*r*theta = 0.5 *12*12*2.617 = 188.424 cm^2 = 0.0188 m^2

 54. Theta =/4; r = 6 cm 55. theta = pi; r = 2 ft 56. theta = 5 pi/3; r = 30 in In numbers 57 - 60, change theta to radians and then find the area of the sector

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