A proton accelerates from rest in a inform electric field of

A proton accelerates from rest in a inform electric field of 6.40 N/C. At some later, its speed is 1.20 times 10^6 m/s. The mass of a proton is 1.673 times 10^-27 kg and the charge of a proton is 1.6 times 10^- C.. What is the magnitude of the acceleration of the proton? How long does it take the proton to reach this speed? How far has it moved m this time interval? What is its kinetic energy at the later time? An electric field of magnitude 3500 N/C is applied along the y axis. Calculate the electric flux through a rectangular plane 0.35 m wide and 0.7 m long if the plane is parallel to

Solution

6)

E = 640 N/C

v = 1.2 *10^6 m/s

mp = 1.673 *10^-27 Kg

q = 1.6 *10^-19 C

a)

let the magnitude of acceleration is a

m * a = E * q

1.673 *10^-27 * a = 640 * 1.6 *10^-19

a = 6.13 *10^10 m/s^2

the acceleration of the proton is 6.13 *10^10 m/s^2

b)

let the time taken is t

1.2 *10^6 = 6.13 *10^10 * t

t = 1.96 *10^-5 s

the time taken is 1.96 *10^-5 s

c)

distance travelled = 0.5 * a * t^2

distance travelled = 0.5 *6.13 *10^10* (1.96 *10^-5)^2

distance travelled = 11.8 m

d)

kinetic energy at later time = 0.5 * m * v^2

kinetic energy at later time = 0.5 * (1.2 *10^6)^2 *1.673 *10^-27

kinetic energy at later time = 1.205 *10^-15 J