Convert the equation to standard from by completing the squa

Convert the equation to standard from by completing the square on x and y. Then graph the and give the location of its 25x^2 + 9y^2 + 250x - 162y + 1129 = 0 The standard form of the equation is Choose the correct graph below. The foci are located at

Solution

25x²+9y²+250x-162y+1129=0

25(x²+10x) +9(y²-18y)+1129=0

25(x²+10x+25-25) +9(y²-18y +81-81)+1129=0

25(x+5)²+9(y-9)^2-625-729+1129=0

25(x+5)²+9(y-9)²=225

(x+5)²/9 + (y-9)²/25 =1

Correct graph is C