Solve SolutionSolution Using sine law sinA a sinB b sinC c

Solution

Solution:

Using sine law:

sinA /a = sinB /b = sinC /c

Here;

sin72^o /9 = sin40^o /b

=> b = 9*sin40^o /sin72^o

=> b = 6.08 = AC

and;

C = 180^o - (A+B)

=> C = 68^o

hence;

sinC/ c = sin72^o /9

=> c = 9*sin68^o/sin72^o

=> c = 8.774 = AB