2Na2O2s 2H20l 4NaOHaq O2g Predict the sign of Change in S

2Na2O2(s) + 2H20(l) --> 4NaOH(aq) + O2(g)

-Predict the sign of Change in S for this reaction and explain.

-Calculate the Change is S from standard molar entropy values. S for Na2O2(s) = 95 J/mol K

Show work step by step.

Delta S = 205.5 + 48.2*4 - 2*69.9 -2*95 = 68.5 J/K

The change in entropy is positive because the moles in reactant mixture is lower than those in product mixture.

Also, the product has gas evolution, which further increases the entropy since gases have relatively higher entropies