Find the equation in slopeintercept form of the line passing

Find the equation (in slope-intercept form) of the line passing through the points with the given coordinates. (4, 3), (-1, -3) Answer

Given coordintes are (4,3) and (-1,-3).

Need to find the equation of line in slope-intercept form.

Let the equation is y = mx+c

substitute (4,3) in y = mx+c

3 = 4m+c

c = 3-4m

Now substitute (-1,-3) in y = mx+c

-3 = (-1)m+c

-3 = -m + c

Substitute c = 3-4m in the above one.

-3 = -m + c

-3 = -m + 3 - 4m

-3 = 3 - 5m

5m = 3 + 3

5m = 6

m = 6/5

Substitute m = 6/5 in

c = 3-4m

c = 3-4(6/5)

c = 3-(24/5)

c = (15-24)/5

c = -9/5

equation of the line is y = (6/5)x+(-9/5)

Therefore, required equation of the line is y = (6/5)x-(9/5)