Denote by PnR the space of all polynomials with real coeffic
Solution
Here n = 2 ,so
let p (x) = ax2 + bx +c
T p(x) = x2 *(d2p/ dx2 ) = x2 * 2a (dp/dx = 2ax + b , hence d2p/ dx2 = 2a)
T (x) = 0 (here a =0, so x2 * 2a = 0)
T (1-x) = 0 (here a = 0 x2 * 2a = 0 )
T (2+x2) = 2*x2 (here a = 1 x2 * 2a = 2*x2 )
Now we have to represent 0, 0 , 2a * x2 in terms of basis {x,1-x,2+x2 }
lets do it for any general quadratic polynomial (ax2 + bx +c )
let c1,c2,c3 be coefficients of corresponding basis
so the equation is
ax2 + bx +c = c1 *x + c2 *(1-x) + c3* (2+x2)
solving we get
c2 + 2*c3 = c (equatting the constant )
- c2 = b (equating the coefficient of x)
c3 = a (equating the coefficient of x2)
so c1 = -2a+b+c, c2 = -b, c3 = a
now for 0 ,a = b = c= 0 , so c1 =c2 = c3 = 0
for 2x2 a = 1, b = c = 0, c1 = -4 , c2 = 0 , c3 = 2
so the representation of matrix T =
| 0 | 0 | -4 |
| 0 | 0 | 0 |
| 0 | 0 | 2 |
