Two computers are connected together through their serial po

Two computers are connected together through their serial ports and Hyper-terminal communication software system The data communication settings between the two computers are as follows: data transmission speed (bps) = 9600 data bits = 8 Parity bit = even stop bit = 2 start bit = 1 If one computer transfers a file size of 38400 bytes to other computer, how many frames of data will be formed for this data transfer. (The answer is an integer number)

Solution

The transfer rate for the link is 9600 bps (bits per second)

Now we have 8 data bits parity bit and start and stop bit.

Given the requirement we will need a frame of 12 bits a simple packet of data.

Now 9600/12=800 frames per second will be transferred

Now 38400 bytes = 38400 * 8 bits = 307200 bits of data needs to be transferred.

Now 307200/12=25,600 frames are required.