A natural body of water has an O2 content of 800 milligrams

A natural body of water has an O2 content of 8.00 milligrams per liter. How many liters of it are required to decompose the organic matter in 1.00 liter of wastewater with a biological oxygen demand (BOD) of 137 mg per liter

Solution

Amount of oxygen needed to decompose the organic matter in 1 liter of wastewater (assuming this is BOD?) = 137 mg/liter * 1 liter = 137 mg oxygen.

How many liters of natural water needed to satisfy this oxygen demand?
137 mg / (8 mg/liter) = 17.125 liters of natural water.

Conclusion: the amount of natural water needed to provide the required amount of oxygen for organic matter decomposition equals 17.125 liters of natural water.

A natural body of water has an O2 content of 8.00 milligrams per liter. How many liters of it are required to decompose the organic matter in 1.00 liter of wast

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