suppose that F is a field with 3 elements01a prove that 11a
suppose that F is a field with 3 elements{0,1,a} prove that 1+1=a , a+1=0 ,a*a= 1.
let F is a field ,prove that if 1+1+1+1=0 in F ,then 1+1=0
Solution
Since F is a field , therefore first we construct the two composition table as for +3 and .3
See table no. 1
and See table no. 2
Now 1+1 =a because F is a field and F IS CLOSED WITH RESPECT TO THE ADDITION. (See table no. 1 )
ALSO a F , 1 F this implies that a+1=0 as F is closed with respect to the addition . (See table no. 1)
Further a F , again from the composition table a*a = 1 .(see table no. 2 )
since F is a field
also we suppose 1+1 = 0 then 1+1+1+1 = (1+1) +(1+1) =(0) + (0) = 0 from composition table 1 and using 1+1 =0.
| +3 | 0 | 1 | a |
| 0 | 0 | 1 | a |
| 1 | 1 | a | 0 |
| a | a | 0 | 1 |
