CHEM40420 VMP 2 Enzyme Kinetics 10 Visualize enzyme turnover

CHEM40420 VMP #2: Enzyme Kinetics 10- Visualize enzyme turnover under each of the four conditions outlined below, using results for E, and E2 as a guide. 6 1. Why is it important that [Sl >> [enzyme]? 2. Why is there a plateau (upper limit for Vo)? 3. Could E, and E2 have the same catalytic efficiency? - E2 + P 0.5 1.0 Increasing Vmax IS)

Solution

1). for a given values of E, The substrate concentration is taken high then rate of formation of product is independent of con. of S and reaches maximum value. if con. S is low then rate of formation of product is proportional to con.S.

2) if substrate concentration contineously increase then there is no vaccant sites and the the rate follows zero order.hence limit value is V₀

3) catalytic efficiency of E₁ is faster than E₂ . it is clearly from graph.