Write a sequence of exactly two MIPS instructions to load th

Write a sequence of exactly two MIPS instructions to load the following hexadecimal value into register $s2: 0x32638270. No pseudo instructions allowed (i.e., no li).

Solution

0:$zero
3:($v0-$v1)
2:($v0-$v1)
6:($v0-$v1)
3:($v0-$v1)
8:($t0-$t7)
2:($v0-$v1)
7:(a1-$a3)

There are many different ways, for example:
1. add $zero, $zero, $zero}
2. sll $zero, $zero, $zero}
3. or $zero, $zero, $zero
li $s0, # Load 32-bit immediate value into s0
This instruction can be implemented a couple of different ways:
lui $s0, ori $s0, $s0,
or lui $s0, addi $s0, $s0,
div $s0, $s1, $s2
# Integer division: s0 = s1/s2 This instruction can be implemented simply using the div instruction.
div $s1, $s2
mflo $s0
Registers:
Smaller instruction encoding may mean smaller programs -- this may be difficult in practice
since the reductions aren’t byte-aligned, so addressing subsequent instructions is difficult.
It also breaks the MIPS tenet of fixed-length instructions. Programs may increase in size
because fewer registers means more data will ’spill’ into memory, leading to more load instructions.