If the volume is increased to 352 L at cornstant temperature

If the volume is increased to 35.2 L. at cornstant temperature, how many this larger containe xt 2.0 2. Gas and with the s around tem

part A)

volume of gas V1 = 4.40 L

number of moleucles = 1050 molecules

volume increased V2 = 36.2 L

volume increases , then number of collisions decreases.

V1 n1 = V2 n2

4.40 x 1050 = 36.2 x n2

n2 = 127.6

number of collisions = 128

Note : number of collisions looks like 1050 . if that is not the value . please just substitute correct value