The specific heat of a metal is determined by heating the we

The specific heat of a metal is determined by heating the weighed metal, adding it to water in a calorimeter, and measuring the temperature change. The specific heat of water is 4.180 Joules per g per °C. The data collected are as follows 1. Grams of water in the calorimeter 47.47 Grams of metal 18.05 Initial temperature of metal 100.48 Initial temperature of water (°C) 22.30 Maximum temperature of water after metal is added (°C) 2351 Calculate the following (1) Temperature fall of metal. (2) Temperature rise of water (3) Joules gained by water (= joules lost by metal). (4) Specific heat of metal.

Solution

(a)

Temperature fall of metal = 100.48-23.51 = 76.97⁰C

(b)

Temperature rise of water = 23.51-22.30 = 1.21⁰C

(c)

Joules gained by water = m*C*dT = 47.47*4.18*1.21 = 240.09 J

(d)

Using relation:

Q = m*C*dT

Putting values:

240.09 = 18.05*C*76.97

Solving we get:

C = 0.173 J/(g.⁰C)

Hope this helps !