solve the problem a 3b 5d c d Let H a b c d in R 3a 9b 4c 11
Solution
1. We have H = span{ v} where v = (a+3b+5d, c+d, --3a-9b+4c,-11d, -c-d)T . Let us perform the following row operations on v:
Add 3times row 1 to row3; Add 1 time row 4 to row 2
Multiply row 3 by ¼; Add 1 time row 3 to row 4.
Then v changes to u = ( a+3b+5d, 0, c+d, 0)T = a(1,0,0,0)T+3b(1,0,0,0)T+c(0,0,1,0)T+ d(5,0,1,0)T so that H = span{(1,0,0,0)T,(0,0,1,0)T,(5,0,1,0)T }. Thus, the dimension of H is 3. Option C is the correct answer.
2. Let A =
1
-4
1
2
3
-10
5
4
Let us reduce A to its RREF as under:
Add -3 times the 1st row to the 2nd row
Multiply the 2nd row by ½
Add 4 times the 2nd row to the 1st row
Then the RREF of A is
1
0
5
-2
0
1
1
-1
The change of coordinates matrix from B to C is
5
-2
1
-1
Option D is the correct answer.
3. Since b1 = c1-5c2 and b2 = 3c1-2c2, the change of basis matrix from B to C is
1
-5
3
-2
Option D is the correct answer:
| 1 | -4 | 1 | 2 |
| 3 | -10 | 5 | 4 |

