Given that n n and tn nn which grows faster Prove it You m

Given that (n) = n! and t(n) = n^n, which grows faster? Prove it. You may not use Stirling\'s Approximation.

Solution

You can use logrithimic approach in order to predict which one having faster order of growth

a^n<n!

for large values of n use logrithimic approch.

Take the log of both sides, you get

nlog(a)=log(a^n)<log(n!)=i=1 to nlog(i)

Now in order to increment n you must have to only add log(a) term to the left side, but the term added to right side log(n+1) is basically large as the value n becomes large. And as the result the value becomes large to the level to make easy differentiate and be greater than nlog(a). So, Factorial is faster than Exponential

 Given that (n) = n! and t(n) = n^n, which grows faster? Prove it. You may not use Stirling\'s Approximation.SolutionYou can use logrithimic approach in order t

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