When copperII sulfate pentahydrate CuSO4 5 H2O is heated it

When copper(II) sulfate pentahydrate (CuSO_{4 *} 5 H₂O) is heated, it decomposes to the dehydrated form. The waters of hydration are released from the solid crystal and form water vapor.

The hydrated form is medium blue, and the dehydrated solid is light blue.

The balanced equation is:

If 6.18 g CuSO_{4 *} 5 H₂O is decomposed to CuSO₄, predict the mass of the remaining light blue solid.

Solution

6.18 g CuSO4*5H2O

Molar mass of CuSO4*5H2O = 160 grams

Now 160 grams contains 90 grams of water

1 grams will contain ( 90/160 )

6.18 grams will contain = (90/160)*6.18 = 3.48 grams

Remaining blue solid = 6.18-3.48 = 2.7 grams

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