Can someone please help me break this question down and come
Can someone please help me break this question down and come up with a step-by-step solution? I appreciate your help.
A researcher raises the temperature from 87.7 to 98.6 ° C and finds that the rate of the reaction doubles. What was the activation energy (in kJ) for this reaction? (R = 8.3145 J/molK)Solution
temperature T1 = 87.7 oC = 360.85 K
temperature T2 = 98.6 oC = 371.75 K
ln (k2 / k1) = Ea / R [1 / T1 - 1 /T2]
ln (2) = Ea / 8.3145 x 10^-3 [1/360.85 - 1/371.75]
Ea = 70.93 Kj/mol
Activation energy = 70.9 kJ
