You have 00100M NaH2PO4 and 00100M Na2HPO4 in your chemical

You have 0.0100M NaH2PO4 and 0.0100M Na2HPO4 in your chemical stores. What would the pH be of a mixture of 100.0 ml of each?

Solution

pH = pka + log[Na2HPO4]/[NaHPO4] , pka for NaHPo4 = 7.198 ,

[Na2HPO4] = (0.01/0.1) = 0.001=[NaHPO4]

pH = 7.198 + log(0.001/0.001)

pH = 7.198

You have 0.0100M NaH2PO4 and 0.0100M Na2HPO4 in your chemical stores. What would the pH be of a mixture of 100.0 ml of each?SolutionpH = pka + log[Na2HPO4]/[NaH

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