You have 00100M NaH2PO4 and 00100M Na2HPO4 in your chemical
You have 0.0100M NaH2PO4 and 0.0100M Na2HPO4 in your chemical stores. What would the pH be of a mixture of 100.0 ml of each?
Solution
pH = pka + log[Na2HPO4]/[NaHPO4] , pka for NaHPo4 = 7.198 ,
[Na2HPO4] = (0.01/0.1) = 0.001=[NaHPO4]
pH = 7.198 + log(0.001/0.001)
pH = 7.198
![You have 0.0100M NaH2PO4 and 0.0100M Na2HPO4 in your chemical stores. What would the pH be of a mixture of 100.0 ml of each?SolutionpH = pka + log[Na2HPO4]/[NaH You have 0.0100M NaH2PO4 and 0.0100M Na2HPO4 in your chemical stores. What would the pH be of a mixture of 100.0 ml of each?SolutionpH = pka + log[Na2HPO4]/[NaH](/WebImages/35/you-have-00100m-nah2po4-and-00100m-na2hpo4-in-your-chemical-1104078-1761583973-0.webp)