Write pseudocode to sum consecutive odd integers Let the low

Write pseudocode to sum consecutive odd integers. Let the lowest odd integer be L and the highest odd integer be H, and let both L and H be provided by the user.

Solution

// C++ code to sum consecutive odd integers from L to H

#include <iostream>
#include <fstream>
#include <string>
#include <cassert>
#include <iomanip>
#include <math.h>
#include <vector>
#include <algorithm>
#include <ctime>
#include <limits.h>
using namespace std;

int main()
{
   //Initialize total to zero
   int total = 0;

   // declaare L and H
   int L, H;

   // input L and H from the user
   cout << \"Enter L: \";
   cin >> L;
   cout << \"Enter H: \";
   cin >> H;

   // for loop from L to H
   for (int value = L; value <= H ; ++value)
   {
       // check if value is odd
       if(value%2 != 0)
           // update total
           total = total + value;
   }

   // print the result
   cout << \"Total: \" << total << endl;


    return 0;
}

/*
output:

Enter L: 11
Enter H: 21
Total: 96

*/

Write pseudocode to sum consecutive odd integers. Let the lowest odd integer be L and the highest odd integer be H, and let both L and H be provided by the user

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