Calculate delta G for H2O g O2 g H2O2 g at 5996K using the

Calculate delta G for H2O (g) + O2 (g) ---> H2O2 (g) at 599.6K using the following data

H2(g) + O2(g) ---> H2O2(g) Kp=2.3x10^6 at 599.6K

2H2(g) + O2(g) ---> 2H2O(g) Kp=1.8x10^37 at 599.6K

H2(g) + O2(g) ---> H2O2(g) ....(i) x 2 Kp=2.3x10^6

DG1 = 2 [-RTln(Kp)] = 145.976 KJ/mol

2H2(g) + O2(g) ---> 2H2O(g) Kp=1.8x10^37

DG2= -RTln(Kp) = 427.431 KJ/mol

Reverse the second reaction, add these two reactions to get

2H2O (g) +2 O2 (g) ---> 2H2O2

Total DG = DG1 + (-DG2) = 145.976 - 427.431 = -281.455 KJ/mol