Show whether or not the relation Solution1 For any real numb

Solution

1.

For any real number,a

a<a is not true.

Hence, it is not reflexive

a<b means b<a cannot be true

Hence it is not symmetric

a<b and b<a can never be both true

So it is not antisymmetric

a<b and b<c implies a<c

Hence it is transitive.