The normal boiling point of liquid propanol is 371 K Assumin

The normal boiling point of liquid propanol is 371 K. Assuming that its molar heat of vaporization is constant at 43.9 kJ/mol, the boiling point of C₃H₇OH when the external pressure is 0.647 atm is K.

Solution

from clausius claperyon equation

ln(p1/p2)=L/R*((1/T1)-(1/T2))

ln(0.647)=43.9*10^(3)((1/371)-(1/T2))

T2=359.98K