Determine all the solutions of the equation 3 sin2 x sin x

Determine all the solutions of the equation:

3 sin2 x + sin x - 1 = 0

Solution

3sin^2 x + sin x -1 = 0

let sin x = y

3 y^2 + y - 1 = 0

solving for y

y = ( -1 + - sqrt (1 + 4*3*1 ) / 6

y = ( -1 + sqrt 13 ) / 6 , ( -1 - sqrt 13 ) / 6

or sin x = ( -1 + sqrt 13 ) / 6 , ( -1 - sqrt 13 ) / 6

x = sin^-1   ( -1 + sqrt 13 ) / 6 + 2n pi , pi - sin^-1 ( -1 + sqrt 13 ) / 6 + 2n pi

x = sin^-1 ( -1 - sqrt 13 ) / 6 + 2 npi , pi +  sin^-1 ( -1 - sqrt 13 ) / 6 + 2 npi

Determine all the solutions of the equation: 3 sin2 x + sin x - 1 = 0Solution3sin^2 x + sin x -1 = 0 let sin x = y 3 y^2 + y - 1 = 0 solving for y y = ( -1 + -

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