Balance the following equation in acidic solution using the

Balance the following equation in acidic solution using the lowest possible integers and give the coefficient of water.
MnO₄^-(aq) + H₂S₂O₃(aq) ? Mn²⁺(aq) + HSO₄^-(aq)

Please explain in detail as to how you got the answer. Thanks

Solution

MnO4- (aq) + __H2SO3 (aq) --> __Mn^2+ (aq) + __HSO4- (aq
MnO4- @ Mn+7 takes 5 electrons --> Mn^2+
H2SO3 @ S+4 --> (HSO4)-1 @ S+6 & 2 electrons lost

we will balance electrons by 5 times H2SO3 ,,,, & 2 times MnO4)-:
2 MnO4- takes 10 electrons --> 1Mn^2+
5 H2SO3 --> 5 (HSO4)-1 & 10 electrons lost

combine:
2 MnO4- & 5 H2SO3 --> 2 Mn^2+ & 5 HSO4-

again if the rest is asked of you:
balance the total of the charges of the ions of both sides, using H+ :
2 (MnO4)-1 & 5 H2SO3 & 1 H+--> 2 Mn2+ & 5 (HSO4)-1

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