Describe the preparation of 12 mL of a 0050 M solution of ea

Describe the preparation of 12 mL of a 0.050 M solution of each of the halogens, using the reactions in the preceding question. Available to you are solid Ca(OCl)₂; 0.20 M solutions of NaCl, NaBr, NaBrO₃, and CuSO₄; a 0.40 M solution of NaI; a 0.50 M solution of H₂SO₄; distilled water; and a 10-mL graduated cylinder (where volumes can be read to the nearest 0.1 mL). Calculate the required quantity of each reagent and the volume of water that must be added for dilution.

a. Chlorine water

b. Bromine water

c. Iodine wate

Solution

you want 12 mL of 0.050 M I₂. so you want (0.0006 mol) of I₂.

So, for 0.0006 moles of I2, you need 0.0012 moles of Cu2+ and 0.0024 moles of I-.

Cu2+ can come from CuSO4 and I- can come from NaI.

0.0012 moles of Cu2+ / 0.20 M CuSO4 is 0.006 L = 6 mL.

0.0024 moles of I- / 0.40 M NaI is 0.006 L = 6 mL.

you have 12 mL total, use it all up with 6m