Determine the magnitude of moment of force P 50 N about lin
Solution
EASY WAY by vectorS;
HOW: find the coordinates of the points B,E these are ( 0,8,9 ) and (0,0,15) wrt the origin and axes given in the figure (origina t O and axes x,y,z). We aim to find the vector eqn of the force.
Coordinates of E ( 0,0,15)
vector eqn of line BE = ( 0,0,15)-(0,8,9) = ( 0,-8, 6)
Hence force along BE is P( BE) = P(0,-8,6)
.
Vector eqn of line OC around which the moment is reqd
do the same way ( coords of C - coords of O) = (12,8,9)-(0,0,0) = (12,8,9)
The moment of Force along BE around line OC is FX OC ( vector cross product) and we want the component along OC so net salar moment is F X OC. OC where (dot) is the dot or scalar product
Finf BE X OC is ( 120i -72j -96k)
take scalar product with OC ( 120i-72j-96k). (12i +8j+9k) = 120*12-72*9-96*9 = 1440 -576- 864 =0
Answer is given, choose it.
Best!!
