Problem A toy train is pushed forward and released at x020m

Problem: A toy train is pushed forward and released at x0=2.0m with a speed of 2.0 m/s. It rolls at a steady speed for 2.0 s, then one wheel begins to stick. The train comes to a stop 6.0 m from the point at which it was released.

1.) What is the magnitude of the train’s acceleration after its wheel begins to stick?

Express your answer using two significant figures.

a= m/s2

Please write out each step with explanation. Thank you so much

Solution

here,

x0 = 2 m

u = 2 m/s

1) let the magnitude of acceleration is a

distance travelled during acceleration , x = 6 - 2 * 2

x = 2 m

Now , using third equation of motion

v^2 - u^2 = 2 * a * x

0 - 2^2 = 2 * a * 2

a = 1 m/s^2

the magnitude of train\'s acceleration is 1 m/s^2