Step 1 fast equilibrium Step 2 slow Step 3 fast 12 21 KEE H2

Step 1 (fast, equilibrium) Step 2 (slow) Step 3 (fast) 12 21 KEE> H2l 2 For which step should one design a catalyst? O 1 O 1and 3 O 3 O 2

Solution

Answer is last option:- 2.

The rate determining step is the slowest step of a chemical reaction that determines the speed (rate) at which the overall reaction proceeds.

the rate determining whis is the slowest step that will tell about the speed of the raection.

The above mechanism the second step is slow step that will be the rate determing step.

 Step 1 (fast, equilibrium) Step 2 (slow) Step 3 (fast) 12 21 KEE> H2l 2 For which step should one design a catalyst? O 1 O 1and 3 O 3 O 2 SolutionAnswer is

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