Part 1 Write both answers to at least two decimal places Par

Part 1   

Write both answers to at least two decimal places.

Part 2

Solution

part 1:

pOH = -log[OH-]

pOH = -log(0.155)

pOH = 0.810

pH + pOH = 14.0

pH + 0.810 = 14.0

pH = 14.0 - 0.810 = 13.2

Therefore, pH = 13.2

part 2:

KOH is a strong base and dissociate completely to give K+ and OH-

pOH = -log[OH-]

pOH = -log(0.155)

pOH = 0.810