A snow blower throws snow 8 et8 at an initial angle of 60 de

A snow blower throws snow 8 et/8 at an initial angle of 60 degree and an initial height of 3ft. At instant a pile of snow is forming 3ft away. How long does it take the snow to travel from the snow blower to the pile? What is the height (h) of the pile at this instant? What is the highest point (H) on the snow\'s projectile path?

Solution

Suppose body starts from point A at 8ft/s at 60 degree angle. The summit of projrctile is at point B and it hits the pile at point C. B is above C by H1.

Height of summit B from A = u^2.(sin60)^2/ g = 2.446 ft.

In the line of start point parallel to start point A (at fall of projectile velocity) in downward direction will be 8cos60= 4 ft/s. At point C, velocity = 0, time taken to hit C = 4/g = 0.4077 s. distance travelled vertically in 0.4077 sec = 4*0.4077 = 1.6308 ft.

Total height of summit from C = 2.446+1.6308 = 4.0768

a. Total time taken from A to snow top = (2usin60/g) + 0.4077 = 1.82s

b. H= 3+2.446 = 5.446 ft

c. h = H-4.0768 = 1.3692 ft.