A B C D F G H I J K 1 Bb Bb BB bb Bb Bb BB BB Bb bb 2 Bb BB
A
B
C
D
F
G
H
I
J
K
1
Bb
Bb
BB
bb
Bb
Bb
BB
BB
Bb
bb
2
Bb
BB
Bb
bb
BB
BB
bb
BB
Bb
Bb
3
BB
Bb
bb
BB
BB
Bb
bb
Bb
Bb
BB
4
BB
bb
Bb
bb
BB
BB
Bb
Bb
Bb
BB
5
bb
bb
Bb
BB
BB
BB
Bb
Bb
BB
Bb
6
Bb
Bb
BB
BB
BB
Bb
bb
bb
BB
BB
7
Bb
Bb
Bb
Bb
BB
BB
BB
Bb
bb
bb
8
BB
Bb
BB
Bb
Bb
BB
bb
Bb
BB
BB
9
Bb
bb
Bb
Bb
BB
Bb
bb
bb
BB
BB
10
bb
Bb
bb
bb
BB
BB
bb
Bb
bb
Bb
A small subgroup of these animals takes off and moves across a wide river to start a new population. In the table above, choose 10 animals at random to move to this island (underline the alleles of the 10 selected). (2 points)
How many BB genotypes are there in the group?_______________
How many Bb genotypes are in the group? ___________________
How many bb genotypes are in the group? ____________________
Work out the allele frequencies for this new group of animals
Allele Frequency for B allele?_______________
Allele Frequency for b allele? ___________________
| A | B | C | D | F | G | H | I | J | K | |
| 1 | Bb | Bb | BB | bb | Bb | Bb | BB | BB | Bb | bb |
| 2 | Bb | BB | Bb | bb | BB | BB | bb | BB | Bb | Bb |
| 3 | BB | Bb | bb | BB | BB | Bb | bb | Bb | Bb | BB |
| 4 | BB | bb | Bb | bb | BB | BB | Bb | Bb | Bb | BB |
| 5 | bb | bb | Bb | BB | BB | BB | Bb | Bb | BB | Bb |
| 6 | Bb | Bb | BB | BB | BB | Bb | bb | bb | BB | BB |
| 7 | Bb | Bb | Bb | Bb | BB | BB | BB | Bb | bb | bb |
| 8 | BB | Bb | BB | Bb | Bb | BB | bb | Bb | BB | BB |
| 9 | Bb | bb | Bb | Bb | BB | Bb | bb | bb | BB | BB |
| 10 | bb | Bb | bb | bb | BB | BB | bb | Bb | bb | Bb |
Solution
Selected 10 animals were : 1A:Bb, 2B:BB, 3C:bb, 4D: bb, 5F:BB, 6G:Bb, 7H: BB, 8I: Bb, 9J: BB, 10K: Bb.
because total 100 population, BB:Bb:BB are in 2:2:1 ratios. according to this
No.of BB genotypes in group are 4
No.of Bb genotypes in group are 4
No.of bb genotypes in group are 2
Allel frequency for B allel:According to hardy weinberg law p+q=1,(p+q)2=1
p2+2pq+q2=1
B allel frequency:[ p2+1/2(pq)]/total= 4+1/2(4)/10=6/10, 0.6
b allel frequency: [q2+1/2(pq)]/total=2+1/2(4)/10=4/10, 0.4
p(B)+q(b)=1, 0.6+0.4=1




