At 250 C a rate constant has the value 521 x 108 L mol1 s1 I

At 25.0 °C, a rate constant has the value 5.21 x 10-8 L mol-1 s-1. If the activation energy is 75.2 kJ/mol, calculate the rate constant when the temperature is 44.0 °C.

Solution

From the Arrhenius equation,

ln (k\'/k) = Ea/R ( 1/T- 1/T\' )

k= 5.21*10-8 at 25(298K)
k\' at 44(317K)

so k\' = 32.13 x 10-8 L mol-1 s-1.