A relation RABCDEF has one and only one candidate key How ma

A relation R(A,B,C,D,E,F) has one and only one candidate key. How many superkeys can there be?
Database class.

Solution

total superkeys = 2^(n-2)

n(A+B+C+D+E+F)= n(A) + n(B) + n(C) + n(D) + n(E) + n(F) - 2(ABCDEF)

So total superkeys --> 2^(n-1) + 2^(n-1) + 2^(n-1)  + 2^(n-1) + 2^(n-1) + 2^(n-1) - 2^(n-6)

A relation R(A,B,C,D,E,F) has one and only one candidate key. How many superkeys can there be? Database class.Solutiontotal superkeys = 2^(n-2) n(A+B+C+D+E+F)=

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