Homework Sourse6 3xx2 1 between 0 and positive infinity Find the absolute e
6- (3x/x^2 +1) between 0 and positive infinity. Find the absolute extrema of the following function on the given interval
Solution
f(x)=6- (3x/x^2 +1)
f\'(x)=(3-3x^2)/(x^2+1)^2
f\'(x)=0
x^2=1
x=-1,+1
f\'\'(1)<0 x=1 maxima
f\'\'(-1)>0 x=-1 minima
Absolute extema at x=-1 and x=1
