3 H2S 1 M CH4110M 4H 22 C Lx Set up the expression for Kc

3. [H2S]. = 1 M, [CH41-1.0M +4H 2(2) C |- Lx Set up the expression for Kc. You do not need to solve for x. D4-7

Solution

You have done absolutely correct.

The expression is as follows:

                2H2S(g)     +     CH4(g)        <-------->     CS2(g)     +     4H2(g)
IC:              1                        1                                     0                      0
C:            - 2x                     - x                                   + x                  + 4x
EC:        1 – 2x                 1 – x                                  x                      4x

Kc = { [CS₂(g)] [H₂(g)]⁴ } / { [H₂S(g)]² [CH₄] }
     = { (x) (4x)⁴ } / { (1 – 2x)² (1 – x) }