Homework SourseA 1 2 3 5 Find the NA This is for an applied linear algebra
A = [1, 2, 3, 5]
Find the N(A).
This is for an applied linear algebra class.
Solution
We know that N(A) is the set of solutions to the equation AX = 0. If X = (x1,x2,x3,x4)T, then this equation is equivalent to x1+2x2+3x3+5x4 = 0 so that x1 = -2x2-3x3-5x4. Then X =(-2x2-3x3-5x4,x2,x3,x4)T = x2(-2,1,0,0)T+ x3(-3,0,1,0)T+x4(-5,0,0,1)T. Hence N(A) = span{(-2,1,0,0)T,(-3,0,1,0)T,(-5,0,0,1)T}.
![A = [1, 2, 3, 5] Find the N(A). This is for an applied linear algebra class.SolutionWe know that N(A) is the set of solutions to the equation AX = 0. If X = (x1](/WebImages/35/a-1-2-3-5-find-the-na-this-is-for-an-applied-linear-algebra-1105877-1761585292-0.webp "A = [1, 2, 3, 5] Find the N(A). This is for an applied linear algebra class.SolutionWe know that N(A) is the set of solutions to the equation AX = 0. If X = (x1")
