In the triangle ABC A 92 degree C 60 degree theta 11 cm F

In the triangle ABC A = 92 degree, C = 60 degree, theta - 11 cm. For the triangle sides and the angle.

Solution

Angle A = 92 degree

Angle C = 60 degree

Then Angle B = 180 - A - C = 180 - 92 - 60 = 28 degree

Now side a = 11 cm

Now a/sinA = b/sinB

b = a(sinB/sinA) = 11*(sin28/sin92) = 5.167 cm

and a/sinA = c/sinC

c = a(sinC/sinA) = 11*(sin60/sin92) = 9.532 cm